int hex в bin

a2b(a,char** b){
   int l=0,t=0;t=a;
   while(t>0){l++;t/=2;}
   b=maloc(t);
   char * p=*b+t-1;
   *p=0;
   t=a;
   while(a>0){
      p--;*p=*("0123456789ABCDEF"+a%16);a/=16;
   }
}

#define HIHEX(h) (h >> (sizeof(unsigned) * 8 - 4))&0xf

char* h2b(unsigned h, char *b)
{
	char *lt[] = { "0000", "0001", "0010", "0011", 
                    "0100", "0101", "0110", "0111", 
                    "1000", "1001", "1010", "1011", 
                    "1100", "1101", "1110", "1111" };
	int i = 0;
	int j = 0;
	while(!HIHEX(h))
		h <<= 4;
	while(h) {
		for(j = 0; j < 4; ++j)
			b[i++] = lt[HIHEX(h)][j];
		h <<= 4;
	}
	return b;
}

int main()
{
	char b[32] = "";
	unsigned h = 0xFFABC01;
	printf("in: %x, out res: %s\n", h, h2b(h, b));
}

itoa(value, str, radix) -> itoa(n, buf, 2) -> profit!!!

-    while(t>0){l++;t/=2;}
+    while(t>0){l++;t/=16;}

in: 1fabc01, out res: 00000001111110101011110000000001
in: 1fabc01, out res: 0000 0001 1111 1010 1011 1100 0000 0001 
in: 1fabc01, out res: 0001 1111 1010 1011 1100 0000 0001 
in: 1fabc01, out res: 1 1111 1010 1011 1100 0000 0001